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Proof step 4 from proof monle-leq (previous step)

m1 +1 = n - m, ⌜n⌝ < # nσ, nσ[n] < nσ[m], mon≤(nσ), m ≤ n, ∀ n, m, nσ. ¬(m1 = n - m ∧ nσ[n] < nσ[m] ∧ ⌜n⌝ < # nσ ∧ mon≤(nσ) ∧ m ≤ n) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
m1 + 1 = n - m, nσ[n] < nσ[m], ⌜n⌝ < # nσ, mon≤(nσ), m ≤ n, ∀ n0, m0, nσ0. m1 ≠ n0 - m0 ∨ ¬ nσ0[n0] < nσ0[m0] ∨ ¬ ⌜n0⌝ < # nσ0 ∨ ¬ mon≤(nσ0) ∨ ¬ m0 ≤ n0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m +1 = m + 1; (s)