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Proof step 10 from proof monls-append1 (previous step)

1 + n < # nl, nl[n + 1] ≤ nl[n], 1 + n < # nl0 + # nl → (nl + nl0)[n] < (nl + nl0)[n + 1] ⊦ nl = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%a: ⊦ (nl + nl0) + nl1 = nl + nl0 + nl1; from specification list[natstream]% ⊦ n < # nl → (nl + nl0)[n] = nl[n]; (s)% ⊦ m + n < m0 → m + n < m0 + n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic