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Proof step 2 from proof monlsinf-notsmall (previous step)

nnf(0) = 0, mon<(⌜nnf⌝ ) ⊦ n < nnf(n + 1) ↔ true

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
nnf(0) = 0, mon<(⌜nnf⌝ ), nnf(n + 1) ≤ n ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)