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Proof step 13 from proof stutf-alltaken (previous step)

nσ[0] = 0, nσ[m0] < nσ[m0 + 1], nσ[m0] < n, ⌜m0⌝ < # nσ, ⌜m0⌝ + ⌜1⌝ < # nσ, n ≤ nσ[m0 + 1], m0 ≤ nσ[m0] → m ≤ nσ[m] ∧ nσ[m] = m0, ∀ n. ⌜n⌝ + ⌜1⌝ < # nσ → nσ[n + 1] = nσ[n] ∨ nσ[n + 1] = nσ[n] + 1 ⊦ nσ = [], ∃ m. m ≤ m0 + 1 ∧ nσ[m] = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
nσ[0] = 0, ⌜m0⌝ + ⌜1⌝ < # nσ, ⌜m0⌝ < # nσ, nσ[m0] < n, nσ[m0] < nσ[m0 + 1], n ≤ nσ[m0 + 1], m0 ≤ nσ[m0] → m ≤ nσ[m] ∧ nσ[m] = m0, ∀ n. ⌜n⌝ + ⌜1⌝ < # nσ → nσ[n + 1] = nσ[n] ∨ nσ[n + 1] = nσ[n] + 1 ⊦ nσ = [], ∃ m. m ≤ m0 + 1 ∧ nσ[m] = n

Proof step 13 from proof stutf-alltaken (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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