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Proof step 18 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, nσ[m0] < nσ[n0], stutf(nσ), m0 ≤ n, nσ[m0] ≤ nσ[n], m0 ≤ n0, ∀ n1. ∃ n0. n1 < n0 ∧ nσ[n0] = nσ[m0] ⊦ nσ[n0] = nσ[m0]

User applied rule all left

And obtained the following new goals

Proof step 19:
# nσ = ∞, nσ[m0] < nσ[n0], stutf(nσ), m0 ≤ n0, nσ[m0] ≤ nσ[n], m0 ≤ n, ∃ n. n0 < n ∧ nσ[n] = nσ[m0] ⊦ nσ[n0] = nσ[m0]

Rule argument

pos: left 7 terms: n0 abort: F discard: T computed: F

Additional information

Used terms: n0