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Proof step 26 from proof stutf-maxinf-is-fin (previous step)

# nσ = ⌜n0⌝ , n < n0, stutf(nσ), m ≤ nσ[n], ∀ n. ∃ n0. n < n0 ∧ ⌜n0⌝ < # nσ ∧ nσ[n0] = m ⊦

User applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n0 abort: F discard: T computed: F

Additional information

Used simplifier rules: lf: ⊦ m < n ∧ n < n0 → m +1 < n0; (forward) from specification nat-basic%trans: ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)% ⊦ m +1 = m + 1; (s)% ⊦ ⌜m⌝ < ⌜n⌝ ↔ m < n; (s)% ⊦ m < n → ¬ n < m; (s) Used terms: n0