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Proof step 34 from proof stutf-maxinf-is-fin (previous step)

stutf(nσ), # nσ = ∞ ∧ (∃ n. ∀ n0. ¬ n0 < n → nσ[n0] = m) ∨ (∀ n. ⌜n⌝ < # nσ → nσ[n] < m) ⊦ ∀ n. ∃ n0. n < n0 ∧ ⌜n0⌝ < # nσ ∧ nσ[n0] = m, ∀ n. ¬ ⌜n⌝ < # nσ ∨ nσ[n] ≠ m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
⌜n0⌝ < # nσ, stutf(nσ), # nσ = ∞ ∧ (∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n0]) ∨ (∀ n. ⌜n⌝ < # nσ → nσ[n] < nσ[n0]) ⊦ ∃ n1. n < n1 ∧ ⌜n1⌝ < # nσ ∧ nσ[n1] = nσ[n0]

Proof step 34 from proof stutf-maxinf-is-fin (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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