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Proof step 43 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, nσ[n2] = nσ[n0], stutf(nσ), n2 ≤ n, ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n0] ⊦ nσ[n + 1] = nσ[n0], ∃ n1. n < n1 ∧ nσ[n1] = nσ[n0]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n + 1

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat% ⊦ m < n → n ≠ 0; (s)% ⊦ ¬ m + n < m; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: n + 1