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Proof step 8 from proof stutf-monle (previous step)

nσ[0] = 0, ⌜n⌝ + ⌜1⌝ < # nσ, nσ[n + 1] < nσ[n], ∀ n. ⌜n⌝ + ⌜1⌝ < # nσ → nσ[n + 1] = nσ[n] ∨ nσ[n + 1] = nσ[n] + 1 ⊦ nσ = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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