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Proof step 4 from proof stutf-notbig (previous step)

⌜n0⌝ + ⌜1⌝ < # nσ, n0 + 1 < nσ[n0 + 1], stutf(nσ), ∀ nσ0. ⌜n0⌝ < # nσ0 ∧ stutf(nσ0) → ¬ n0 < nσ0[n0] ⊦

User applied rule all left

And obtained the following new goals

Proof step 5:
n0 + 1 < nσ[n0 + 1], ⌜n0⌝ + ⌜1⌝ < # nσ, stutf(nσ), ⌜n0⌝ < # nσ ∧ stutf(nσ) → ¬ n0 < nσ[n0] ⊦

Rule argument

pos: left 4 terms: nσ abort: F discard: T computed: T

Additional information

Used terms: nσ