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Proof step 20 from proof not-always-decrease (previous step)

● □ ⟨a0 := A⟩ (◇ A ≪ a0), ⟨a0 := A⟩ (◇ A ≪ a0), ∀ a1. a1 ≪ a0 → \A ∀ A, a. a1 ≠ A ∨ ¬ □ ⟨a := A⟩ (◇ A ≪ a) ∨ a ≠ A, a0 = A ⊦ ∃ a. ◇ (a = A ∧ A ≪ a0)

User applied rule weakening

And obtained the following new goals

Proof step 21:
⟨a0 := A⟩ (◇ A ≪ a0), a0 = A ⊦ ∃ a. ◇ (a = A ∧ A ≪ a0)

Rule argument

poslist: left 1, left 3

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