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Proof step 4 from proof irrefl (previous step)

⊦ ∀ a. (∀ a0. a0 ≪ a → (∀ a. ¬(a0 = a ∧ a ≪ a))) → (∀ a1. ¬(a = a1 ∧ a1 ≪ a1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information