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Proof step 10 from proof wand-left (previous step)

((Q0 * (P0 -* P1)))(H), Q0 ⊆ P0 ⊦ P1(H), Q1(H)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ ((P0 * P1))(H) ↔ (∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ P0(H0) ∧ P1(H1))
Proof step 12:
Q0 ⊆ P0, ∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ Q0(H0) ∧ ((P0 -* P1))(H1) ⊦ P1(H), Q1(H)

Rule argument

spec: heap-sep name: sep seq: ⊦ ((P0 * P1))(H) ↔ (∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ P0(H0) ∧ P1(H1)) subst: [H, P1, P0] → [H, P0 -* P1, Q0] flags: <all paths>

Additional information

Used terms: H, P0 -* P1, Q0