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Proof step 6 from proof wand-right (
previous step
)
∀ H. ((P * Q0))(H) → Q1(H) ⊦ ∀ H. P(H) → ((Q0 -* Q1))(H)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 7
:
P(H), ∀ H. ((P * Q0))(H) → Q1(H) ⊦ ((Q0 -* Q1))(H)
Rule argument
Additional information