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Proof step 9 from proof wand-right (previous step)

P(H), ∀ H. ((P * Q0))(H) → Q1(H) ⊦ ∀ H1. H1 ⊥ H ∧ Q0(H1) → Q1(H1 ∪ H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
P(H), Q0(H0), H0 ⊥ H, ∀ H. ((P * Q0))(H) → Q1(H) ⊦ Q1(H0 ∪ H)

Rule argument

Additional information