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Proof step 13 from proof cf-map-unknown (previous step)

cf(r) = a × r0, rs1 ∩ rs0 = ∅, R[rs0, cf, af], o[r => ce][rs1, cf, af] ⊦ (o[r => a × r0] * R)[rs1 ∪ rs0, cf, af], o[r => a × r0][rs1, cf, af] ∧ R[rs0, cf, af] ∧ rs1 ∩ rs0 = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
cf(r) = a × r0, rs1 ∩ rs0 = ∅, o[r => ce][rs1, cf, af], R[rs0, cf, af] ⊦ (o[r => a × r0] * R)[rs1 ∪ rs0, cf, af], o[r => a × r0][rs1, cf, af]

Proof step 13 from proof cf-map-unknown (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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