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Proof step 52 from proof cf-map-unknown (previous step)

cf(r) = a × r0, rs1 ∩ rs0 = ∅, ((r => ce))(mk(rs1, cf)), R[rs0, cf, af], r1 ∈ rs1, ∀ r. r ∈ rs1 → af(r) = o ⊦ # rs1 = 0, af(r1) = o, rs1 = ∅, (o[r => a × r0] * R)[rs1 ∪ rs0, cf, af]

Heuristic quantifier closing applied rule all left

And obtained the following new goals

Proof step 53:
cf(r) = a × r0, rs1 ∩ rs0 = ∅, ((r => ce))(mk(rs1, cf)), R[rs0, cf, af], r1 ∈ rs1, r0 ∈ rs1 → af(r0) = o, ∀ r. r ∈ rs1 → af(r) = o ⊦ # rs1 = 0, af(r1) = o, rs1 = ∅, (o[r => a × r0] * R)[rs1 ∪ rs0, cf, af]

Rule argument

pos: left 6 terms: r0

Additional information

Used terms: r0