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Proof step 12 from proof alloc (previous step)

(a[r =>_] * R)[rs ++ r, f, g(r; a)] ⊦ r = null, r ∈ rs, ∃ a. (a[r =>_] * R)[rs ++ r, f, g]

User applied rule exists right

And obtained the following new goals

Proof step 13:
(a[r =>_] * R)[rs ++ r, f, g(r; a)] ⊦ r = null, (g(r)[r =>_] * R)[rs ++ r, f, g], r ∈ rs

Rule argument

pos: right 3 terms: g(r) abort: F discard: T computed: F

Additional information

Used terms: g(r)