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Proof step 3 from proof and-split (previous step)

⊦ ((R ∧ R0))(mk(rs, f, g)) ↔ R[rs, f, g] ∧ R0[rs, f, g]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ R[rs, f, g] ↔ R(mk(rs, f, g))
Proof step 5:
⊦ ((R ∧ R0))(mk(rs, f, g)) ↔ R(mk(rs, f, g)) ∧ R0[rs, f, g]

Rule argument

spec: heap-fun, inst: heap-aux name: apply seq: ⊦ R[rs, f, g] ↔ R(mk(rs, f, g)) subst: [g, f, rs, R] → [g, f, rs, R] flags: <all paths>

Additional information

Used terms: g, f, rs, R