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Proof step 49 from proof aux-known (previous step)

∃ rs0, rs1. rs0 ∪ rs1 = rs ∧ rs0 ∩ rs1 = ∅ ∧ a1[r => o][rs0, f, g(r; a1)] ∧ R[rs1, f, g(r; a1)] ⊦ (g(r)[r => o] * R)[rs, f, g]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information