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Proof step 68 from proof aux-known (previous step)

rs1 ∩ rs0 = ∅, R[rs0, f, g], a1[r => o][rs1, f, g(r; a1)] ⊦ (g(r)[r => o] * R)[rs1 ∪ rs0, f, g], r ∈ rs0, g(r)[r => o][rs1, f, g] ∧ R[rs0, f, g]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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