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Proof step 2 from proof aux-unknown (previous step)

(a0[r =>_] * R)[rs, f, g] ⊦ (a1[r =>_] * R)[rs, f, g(r; a1)] ∧ g(r) = a0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ r =>_ = _∃(λ o. r => o)
Proof step 4:
(a0[_∃(λ o. r => o)] * R)[rs, f, g] ⊦ (a1[_∃(λ o. r => o)] * R)[rs, f, g(r; a1)] ∧ g(r) = a0

Rule argument

spec: maplet name: mapex seq: ⊦ r =>_ = _∃(λ o. r => o) subst: [r] → [r] flags: <all paths>

Additional information

Used terms: r