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Proof step 5 from proof aux-unknown (previous step)

(a0[r => o] * R)[rs, f, g] ⊦ ∃ o. (a1[r => o] * R)[rs, f, g(r; a1)]

User applied rule exists right

And obtained the following new goals

Proof step 6:
(a0[r => o] * R)[rs, f, g] ⊦ (a1[r => o] * R)[rs, f, g(r; a1)]

Rule argument

pos: right 1 terms: o abort: F discard: T computed: T

Additional information

Used terms: o