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Proof step 44 from proof embed-split (previous step)

mk(rs, f, g) = mk(rs0, f0, g0) ∪ Ha, a[P0](mk(rs0, f0, g0)), a[P1](Ha), mk(rs0, f0, g0) ⊥ Ha ⊦ a[P0 * P1](mk(rs, f, g))

User applied rule apply lemma

And obtained the following new goals

Proof step 45:
⊦ ∃ rs, f, g. Ha = mk(rs, f, g)
Proof step 46:
mk(rs, f, g) = mk(rs0, f0, g0) ∪ Ha, a[P1](Ha), a[P0](mk(rs0, f0, g0)), mk(rs0, f0, g0) ⊥ Ha, ∃ rs, f, g. Ha = mk(rs, f, g) ⊦ a[P0 * P1](mk(rs, f, g))

Rule argument

spec: heap-fun, inst: heap-aux name: mk-exists seq: ⊦ ∃ rs, f, g. Ha = mk(rs, f, g) subst: [Ha] → [Ha]

Additional information

Used terms: Ha