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Proof step 75 from proof embed-split (previous step)

mk(rs, f, g) = mk(rs0, f0, g0) ∪ mk(rs1, f1, g1), rs0 ∩ rs1 = ∅, a[P0](mk(rs0, f0, g0)), a[P1](mk(rs1, f1, g1)), r ∈ rs ⊦ # rs = 0, g(r) = a, rs = ∅

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 76:
⊦ a[P](mk(rs, f, g)) ↔ P(mk(rs, f)) ∧ (∀ r. r ∈ rs → g(r) = a)
Proof step 77:
mk(rs, f, g) = mk(rs0, f0, g0) ∪ mk(rs1, f1, g1), rs0 ∩ rs1 = ∅, P1(mk(rs1, f1)), a[P0](mk(rs0, f0, g0)), r ∈ rs, ∀ r. r ∈ rs1 → g1(r) = a ⊦ # rs = 0, g(r) = a, rs = ∅

Rule argument

spec: <toplevel> name: lift-aux seq: ⊦ a[P](mk(rs, f, g)) ↔ P(mk(rs, f)) ∧ (∀ r. r ∈ rs → g(r) = a) subst: [g, f, rs, P, a] → [g1, f1, rs1, P1, a] flags: <all paths>

Additional information

Used terms: g1, f1, rs1, P1, a