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Proof step 13 from proof lift-ex-o (previous step)

oP(o)(mk(rs, f)), ∀ r. r ∈ rs → g(r) = a ⊦ ∃ o. a[oP(o)](mk(rs, f, g))

User applied rule exists right

And obtained the following new goals

Proof step 14:
oP(o)(mk(rs, f)), ∀ r. r ∈ rs → g(r) = a ⊦ a[oP(o)](mk(rs, f, g)), ∃ o. a[oP(o)](mk(rs, f, g))

Rule argument

pos: right 1 terms: o abort: F discard: F computed: T

Additional information

Used terms: o