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Proof step 22 from proof lift-ex-o (previous step)

oP(o)(mk(rs, f)), ∀ r. r ∈ rs → g(r) = a ⊦ (∃ o. oP(o)(mk(rs, f))) ∧ (r ∈ rs → g(r) = a)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
oP(o)(mk(rs, f)), ∀ r. r ∈ rs → g(r) = a ⊦ (∃ o. oP(o)(mk(rs, f))) ∧ (r ∈ rs → g(r) = a)

Rule argument

Additional information