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Proof step 26 from proof lift-ex-o (previous step)

oP(o)(mk(rs, f)), r ∈ rs, ∀ r. r ∈ rs → g(r) = a ⊦ # rs = 0, g(r) = a, rs = ∅

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: r

Additional information

Used terms: r