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Proof step 3 from proof lift-ex-o (
previous step
)
⊦ ∀ rs, f, g. a[_∃ oP][rs, f, g] ↔ (_∃(λ o, a0. a[oP(o)]))[rs, f, g]
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 4
:
⊦ a[_∃ oP][rs, f, g] ↔ (_∃(λ o, a0. a[oP(o)]))[rs, f, g]
Rule argument
Additional information