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Proof step 10 from proof lift-ex-r (previous step)

rP(r)(mk(rs, f)), ∀ r. r ∈ rs → g(r) = a ⊦ ∃ r. a[rP(r)](mk(rs, f, g))

User applied rule exists right

And obtained the following new goals

Proof step 11:
rP(r)(mk(rs, f)), ∀ r. r ∈ rs → g(r) = a ⊦ a[rP(r)](mk(rs, f, g))

Rule argument

pos: right 1 terms: r abort: F discard: T computed: T

Additional information

Used terms: r