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Proof step 26 from proof lift-ex-r (
previous step
)
rP(r)(mk(rs, f)), r0 ∈ rs, ∀ r. r ∈ rs → g(r) = a ⊦ # rs = 0, g(r0) = a, rs = ∅
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 3 terms: r0
Additional information
Used terms: r0