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Proof step 3 from proof lift-false (previous step)

⊦ ∀ rs, f, g. a[false][rs, f, g] ↔ (false)[rs, f, g]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ (false)[rs, f, g]; (s)