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Proof step 1 from proof lift-true (conclusion)

⊦ a[true][rs, f, g] ↔ (∀ r. r ∈ rs → g(r) = a)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ R[rs, f, g] ↔ R(mk(rs, f, g))
Proof step 3:
⊦ a[true](mk(rs, f, g)) ↔ (∀ r. r ∈ rs → g(r) = a)

Rule argument

spec: heap-fun, inst: heap-aux name: apply seq: ⊦ R[rs, f, g] ↔ R(mk(rs, f, g)) subst: [g, f, rs, R] → [g, f, rs, a[true]] flags: <all paths>

Additional information

Used terms: g, f, rs, a[true]