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Proof step 11 from proof lift-unknown (previous step)

rs1 ∩ rs0 = ∅, R[rs0, f, g], r ==>(o, a)[rs1, f, g] ⊦ (a[r =>_] * R)[rs1 ∪ rs0, f, g], a[r =>_][rs1, f, g] ∧ R[rs0, f, g] ∧ rs1 ∩ rs0 = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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