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Proof step 25 from proof lift-unknown (previous step)

mk(rs1, f, g) = (∅ ++ r)[r, o, a], rs1 ∩ rs0 = ∅, R[rs0, f, g] ⊦ r = null, ∃ o. (a[r => o] * R)[rs1 ∪ rs0, f, g], (∃ o. ((r => o))(mk(rs1, f))) ∧ (r0 ∈ rs1 → g(r0) = a)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 26:
⊦ Ha0 = Ha1 ↔ (∀ r. (r ∈ Ha0 ↔ r ∈ Ha1) ∧ (r ∈ Ha0 → Ha0[r]o = Ha1[r]o ∧ Ha0[r]a = Ha1[r]a))
Proof step 27:
rs1 ∩ rs0 = ∅, R[rs0, f, g], ∀ r0. (r0 ∈ mk(rs1, f, g) ↔ r0 ∈ (∅ ++ r)[r, o, a]) ∧ (r0 ∈ mk(rs1, f, g) → mk(rs1, f, g)[r0]o = (∅ ++ r)[r, o, a][r0]o ∧ mk(rs1, f, g)[r0]a = (∅ ++ r)[r, o, a][r0]a) ⊦ r = null, ∃ o. (a[r => o] * R)[rs1 ∪ rs0, f, g], (∃ o. ((r => o))(mk(rs1, f))) ∧ (r0 ∈ rs1 → g(r0) = a)

Rule argument

spec: heap, inst: heap-aux name: ext seq: ⊦ Ha0 = Ha1 ↔ (∀ r. (r ∈ Ha0 ↔ r ∈ Ha1) ∧ (r ∈ Ha0 → Ha0[r]o = Ha1[r]o ∧ Ha0[r]a = Ha1[r]a)) subst: [Ha1, Ha0] → [(∅ ++ r)[r, o, a], mk(rs1, f, g)] flags: <all paths>

Additional information

Used terms: (∅ ++ r)[r, o, a], mk(rs1, f, g)