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Proof step 47 from proof lift-unknown (previous step)

rs1 ∩ rs0 = ∅, R[rs0, f, g], a[r =>_][rs1, f, g] ⊦ (r ==>_ * R)[rs1 ∪ rs0, f, g], r ==>_[rs1, f, g] ∧ R[rs0, f, g] ∧ rs1 ∩ rs0 = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information