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Proof step 5 from proof lift-unknown (
previous step
)
(r ==>(o, a) * R)[rs, f, g] ⊦ ∃ a. (a[r =>_] * R)[rs, f, g]
User applied rule exists right
And obtained the following new goals
Proof step 6
:
(r ==>(o, a) * R)[rs, f, g] ⊦ (a[r =>_] * R)[rs, f, g]
Rule argument
pos: right 1 terms: a abort: F discard: T computed: T
Additional information
Used terms: a