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Proof step 59 from proof lift-unknown (previous step)

mk(rs1, f) = (∅ ++ r)[r, o], rs1 ∩ rs0 = ∅, R[rs0, f, g], ∀ r. r ∈ rs1 → g(r) = a ⊦ r = null, r ==>_[rs1, f, g], (r ==>_ * R)[rs1 ∪ rs0, f, g]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 60:
⊦ R[rs, f, g] ↔ R(mk(rs, f, g))
Proof step 61:
mk(rs1, f) = (∅ ++ r)[r, o], rs1 ∩ rs0 = ∅, R[rs0, f, g], ∀ r. r ∈ rs1 → g(r) = a ⊦ r = null, r ==>_(mk(rs1, f, g)), (r ==>_ * R)[rs1 ∪ rs0, f, g]

Rule argument

spec: heap-fun, inst: heap-aux name: apply seq: ⊦ R[rs, f, g] ↔ R(mk(rs, f, g)) subst: [g, f, rs, R] → [g, f, rs1, r ==>_] flags: <all paths>

Additional information

Used terms: g, f, rs1, r ==>_