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Proof step 80 from proof lift-unknown (previous step)

rs1 ∩ rs0 = ∅, R[rs0, f, g], r0 ∈ rs1, ∀ r0. (r0 ∈ rs1 ↔ r0 = r) ∧ (r0 ∈ rs1 → f(r0) = (r0 = r ⊃ o;(∅ ++ r)[r0])), ∀ r. r ∈ rs1 → g(r) = a ⊦ # rs1 = 0, r = null, r0 = r, rs1 = ∅, ∃ o, a. (r ==>(o, a) * R)[rs1 ∪ rs0, f, g]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: r0

Additional information

Used terms: r0