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Proof step 7 from proof map-same (previous step)

rs1 ∩ rs0 = ∅, (a0[r => o0] * R)[rs0, f, g], a[r => o][rs1, f, g], r ∈ rs1, r ∈ rs0 ⊦

User applied rule weakening

And obtained the following new goals

Proof step 8:
rs1 ∩ rs0 = ∅, r ∈ rs0, r ∈ rs1 ⊦

Rule argument

poslist: left 3, left 2

Additional information