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Proof step 22 from proof merge-owned (previous step)

rs2 ∩ rs = ∅, rs1 ∩ rs0 = ∅, rs2 ∪ rs = rs1 ∪ rs0, a0[P0][rs2, f, g], R0[rs, f, g], a[P][rs1, f, g], R[rs0, f, g], r ∈ rs2 ⊦ # rs2 = 0, a0 = a, rs2 = ∅, (a[P] * a0[P0] * true)[rs1 ∪ rs0, f, g], r ∈ rs0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ R[rs, f, g] ↔ R(mk(rs, f, g))
Proof step 24:
rs1 ∩ rs0 = ∅, rs2 ∩ rs = ∅, rs2 ∪ rs = rs1 ∪ rs0, R[rs0, f, g], a[P](mk(rs1, f, g)), R0[rs, f, g], a0[P0][rs2, f, g], r ∈ rs2 ⊦ # rs2 = 0, a0 = a, rs2 = ∅, (a[P] * a0[P0] * true)[rs1 ∪ rs0, f, g], r ∈ rs0

Rule argument

spec: heap-fun, inst: heap-aux name: apply seq: ⊦ R[rs, f, g] ↔ R(mk(rs, f, g)) subst: [g, f, rs, R] → [g, f, rs1, a[P]] flags: <all paths>

Additional information

Used terms: g, f, rs1, a[P]