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Proof step 35 from proof merge-owned (previous step)

rs2 ∩ rs = ∅, rs1 ∩ rs0 = ∅, P(mk(rs1, f)), P0(mk(rs2, f)), R0[rs, f, g], R[rs0, f, g], r ∈ rs2, r ∈ rs1 → g(r) = a, ∀ r. r ∈ rs2 ∪ rs ↔ r ∈ rs1 ∪ rs0, ∀ r. r ∈ rs1 → g(r) = a, ∀ r. r ∈ rs2 → g(r) = a0 ⊦ # rs2 = 0, a0 = a, rs2 = ∅, (a[P] * a0[P0] * true)[rs1 ∪ rs0, f, g], r ∈ rs0

User applied rule all left

And obtained the following new goals

Proof step 36:
rs1 ∩ rs0 = ∅, rs2 ∩ rs = ∅, P(mk(rs1, f)), P0(mk(rs2, f)), R[rs0, f, g], R0[rs, f, g], r ∈ rs2, r ∈ rs1 → g(r) = a, r ∈ rs2 → g(r) = a0, ∀ r. r ∈ rs2 → g(r) = a0, ∀ r. r ∈ rs1 → g(r) = a, ∀ r. r ∈ rs2 ∪ rs ↔ r ∈ rs1 ∪ rs0 ⊦ # rs2 = 0, a0 = a, rs2 = ∅, (a[P] * a0[P0] * true)[rs1 ∪ rs0, f, g], r ∈ rs0

Rule argument

pos: left 11 terms: r abort: F discard: F computed: T

Additional information

Used terms: r