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Proof step 3 from proof mod-other-aux (previous step)

(a[P] * R)[rs, f, g] ⊦ g(r) = a, (a[P] * true)[rs, f, g(r; a0)]

User applied rule cut formula

And obtained the following new goals

Proof step 4:
f = f(r; f(r)), (a[P] * R)[rs, f, g] ⊦ g(r) = a, (a[P] * true)[rs, f, g(r; a0)]
Proof step 7:
(a[P] * R)[rs, f, g] ⊦ f = f(r; f(r)), g(r) = a, (a[P] * true)[rs, f, g(r; a0)]

Rule argument

fma: f = f(r; f(r))

Additional information

Used formulas: f = f(r; f(r))