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Proof step 9 from proof mod-other-both (previous step)

rs1 ∩ rs0 = ∅, a[P][rs1, f, g], R[rs0, f, g] ⊦ g(r) = a, (a[P] * true)[rs1 ∪ rs0, f(r; o), g(r; a0)], a[P][rs1, f(r; o), g(r; a0)]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ R[rs, f, g] ↔ R(mk(rs, f, g))
Proof step 11:
rs1 ∩ rs0 = ∅, R[rs0, f, g], a[P](mk(rs1, f, g)) ⊦ g(r) = a, a[P][rs1, f(r; o), g(r; a0)], (a[P] * true)[rs1 ∪ rs0, f(r; o), g(r; a0)]

Rule argument

spec: heap-fun, inst: heap-aux name: apply seq: ⊦ R[rs, f, g] ↔ R(mk(rs, f, g)) subst: [g, f, rs, R] → [g, f, rs1, a[P]] flags: <all paths>

Additional information

Used terms: g, f, rs1, a[P]