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Proof step 1 from proof mod-other-hp2 (conclusion)

⊦ g(r) ≠ a ∧ g(r) ≠ a0 ∧ (a[P] * a0[P0] * R)[rs, f, g] → (a[P] * a0[P0] * true)[rs, f(r; o), g]

System applied rule normalize

And obtained the following new goals

Proof step 2:
(a[P] * a0[P0] * R)[rs, f, g] ⊦ g(r) = a0, g(r) = a, (a[P] * a0[P0] * true)[rs, f(r; o), g]

Rule argument

Additional information