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Proof step 21 from proof mod-other-hp2 (previous step)

rs2 ∩ rs = ∅, rs1 ∩ rs2 = ∅, rs1 ∩ rs = ∅, P(mk(rs1, f)), a0[P0][rs2, f, g], R[rs, f, g], ∀ r. r ∈ rs1 → g(r) = a ⊦ g(r) = a0, g(r) = a, (a[P] * a0[P0] * true)[rs1 ∪ rs2 ∪ rs, f(r; o), g], P(mk(rs1, f(r; o))) ∧ (∀ r. r ∈ rs1 → g(r) = a)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
rs1 ∩ rs = ∅, rs1 ∩ rs2 = ∅, rs2 ∩ rs = ∅, P(mk(rs1, f)), R[rs, f, g], a0[P0][rs2, f, g], ∀ r. r ∈ rs1 → g(r) = a ⊦ g(r) = a, g(r) = a0, P(mk(rs1, f(r; o))), (a[P] * a0[P0] * true)[rs1 ∪ rs2 ∪ rs, f(r; o), g]

Proof step 21 from proof mod-other-hp2 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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