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Proof step 7 from proof switch-aux (previous step)

⊦ R(mk(rs, f, g(r; a))) ↔ R(mk(rs, f, g)), r ∈ rs

User applied rule cut formula

And obtained the following new goals

Proof step 8:
⊦ R(mk(rs, f, g(r; a))) ↔ R(mk(rs, f, g)), mk(rs, f, g(r; a)) = mk(rs, f, g), r ∈ rs

Rule argument

fma: mk(rs, f, g(r; a)) = mk(rs, f, g)

Additional information

Used formulas: mk(rs, f, g(r; a)) = mk(rs, f, g)