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Proof step 106 from proof write-known (previous step)

rs1 ∩ rs0 = ∅, ((r => o1))(mk(rs1, f(r; o1))), R[rs0, f, g], ∀ r. r ∈ rs1 → g(r) = a ⊦ a[r => f(r)](mk(rs1, f, g)), (a[r => f(r)] * R)[rs1 ∪ rs0, f, g], r ∈ rs0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 107:
rs1 ∩ rs0 = ∅, ((r => o1))(mk(rs1, f(r; o1))), R[rs0, f, g], ∀ r. r ∈ rs1 → g(r) = a ⊦ (a[r => f(r)] * R)[rs1 ∪ rs0, f, g], a[r => f(r)](mk(rs1, f, g)), r ∈ rs0

Proof step 106 from proof write-known (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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