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Proof step 119 from proof write-known (previous step)

rs1 ∩ rs0 = ∅, R[rs0, f, g], ∀ r. r ∈ rs1 → g(r) = a, ∀ r0. (r0 ∈ rs1 ↔ r0 = r) ∧ (r0 ∈ rs1 → (r = r0 ⊃ o1;f(r0)) = (r0 = r ⊃ o1;(∅ ++ r)[r0])) ⊦ r = null, (a[r => f(r)] * R)[rs1 ∪ rs0, f, g], r ∈ rs0, (r0 ∈ rs1 ↔ r0 = r) ∧ (r0 ∈ rs1 → f(r0) = (r0 = r ⊃ f(r);(∅ ++ r)[r0]))

User applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: r0 abort: F discard: F computed: T

Additional information

Used terms: r0