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Proof step 80 from proof write-known (previous step)

∃ rs0, rs1. rs0 ∪ rs1 = rs ∧ rs0 ∩ rs1 = ∅ ∧ a[r => o1][rs0, f(r; o1), g] ∧ R[rs1, f(r; o1), g] ⊦ (a[r => f(r)] * R)[rs, f, g]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information